Problems/Erdos Discrepancy Problem

Erdos Discrepancy Problem

CombinatoricsSOLVED
Year
1932
Difficulty
*****
Solved by
Terence Tao (2015)

Statement

For any infinite +/-1 sequence, partial sums along arithmetic progressions are unbounded.

sup⁡N,d≥1∣∑k=1Nxkd∣=∞\sup_{N,d \geq 1} \left|\sum_{k=1}^{N} x_{kd}\right| = \infty

About this Problem

Open for 83 years. A 2010 Polymath project used SAT solvers for partial progress. Tao proved it in 2015 using entropy methods and the Elliott conjecture.

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